Sunday, 3 May 2015

Time for some fun

Righty-o, time for some fun, my friends!! (I've been so looking forward to posting this! Can you tell?!) I have below a number of puzzles, some harder than others. 13 in total. Your task is to see how many you can solve all by yourself. Obviously the aim is to have some fun, so don't worry if you've seen any before or if you can't work out any of them. They are all entirely possible. :)

Once you have solved them (or gotten tired of trying to solve them and want to give up), highlight the white space under the question. I've written the answers there, but made the text white, so it won't show up until you highlight it. :)

Have fun!


1. Prove that seven is half of twelve.
Write twelve in Roman numerals - XII. Halve the number by drawing a line horizontally across its center. The upper half is VII.

2. Place three sixes together so as to make seven.
The answer to this is a fraction - I would write it as a fraction but Blogger won't let me! It's 6 6/6


3. What lives in winter, dies in summer, and grows with its roots upwards?
An icicle.

4. Express 100 by repetition of the same figure six times over.
Another fraction one. 99 99/99 = 100.

5. What is the surest way of keeping water from entering your house?
Don't pay your water bill.

6. Five herrings were divided among five persons. Each had a herring and yet one remained in the dish. How was this managed?
The last of the five received his herring in the dish.

7. What gets bigger the more you contract it?
Debt.

8. Prove that two sixes make eleven.
This is dependent on the use of Roman numerals. One six (VI) is placed above another six, but the latter in an inverted position, the combination making XI. 

9. What speaks all languages?
An echo.

10. You undertake to show another person something which you never saw before, which he never saw before, and which, after you both have seen it, no one else will ever see again. How is it to be done?
The puzzle is solved by cracking a nut, showing your interlocutor the kernel, then eating it.

11. How many times can you subtract 5 from 135?
Only once. After that it isn't 135 anymore.

12. You undertake to put something into a person's left hand which he cannot possibly take in his right. How is it to be done?
You place in the person's left hand his own right elbow, which, obviously, he cannot take in his right hand.

13. Take one from nineteen and leave twenty.
Write nineteen in Roman numerals - XIX. Remove the I and you have XX, which is twenty.


Did you get any of them wrong?
Do you have any puzzles for me? Leave them in the comments. :)
Happy May everyone!
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8 comments:

  1. I leave my front door, run on a level road for some distance, then run to the top of a hill and return home by the same route. I run 8 mph on level ground, 6 mph uphill, and 12 mph downhill. If my total trip took 2 hours, how far did I run?
    Solution:
    http://www.futilitycloset.com/2015/04/02/mileage/
    Over 600 other puzzles:
    http://www.futilitycloset.com/category/puzzles/

    ReplyDelete
    Replies
    1. That's a great one. Thanks for sharing!

      Delete
  2. We play a similar game to #2 in the car: Look for a number-plate with four numerals and try turn them into 10, for example 5363 would be 5+6-(3/3)

    #4 9999÷99=101 not 100

    #5 Turning of the main valve is surer

    #9 Google

    #11 Answer is infinitely either you continue subtracting into negative infinity or get a new 135 each time

    ReplyDelete
  3. :) Thanks for commenting!

    #4 The answer is 99 99/99 (99, not 9999) lol :)

    ReplyDelete
    Replies
    1. Another answer would be 5x(5+5)+5x(5+5)

      Delete
    2. That is actually a very good point.
      I actually got those puzzles out of a book I found in the library. You'd probably really enjoy it.

      Delete

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